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The marketing research department for a computer company used a large city to test market their new product. They found that the demand equation was p = 1296 – 0.12x^2. If the cost equation is C = 830 + 396x, find the number of units that will produce maximum profit.

The marketing research department for a computer company used a large city to test market their new product. They found that the demand equation was p = 1296 – 0.12x^2. If the cost equation is C = 830 + 396x, find the number of units that will produce maximum profit.
Haha. That’s the given question. I don’t know anything more than that.

Here is the situation. I have 6 numbers that have to be randomly arranged into 6 positions. I have 3 tries to get all 6 numbers in the right postion. It is possible for some numbers to stay in their original position, but that is irrelevant right now. I figured out 2 of the numbers and I am on the last try. The number 6 can either go in position 4 or 5; the number 0 can either go in position 1, 4, or 6; the number 1 can either go in position 5 or 6; the number 4 can either go in position 4 or 6. Does anyone have a way of figuring the best probablities of where each number could be positioned, or is there an online tool that can help me figure this out?
I think the question is misunderstood. I am not looking for the number of combinations for the 6 digits. It works like this. I have the digits 4,6,2,1,5,3. There is a secret combination of these numbers that has been predetermined. I have 3 chances to figure out this combination. Since some numbers can remain in their original position I always leave every number in its same spot on the first spin, so-to-speak. The 2 was the only one that was correct. That means that 4,6,1,5,3 are eliminated from postions 1,2,4,5,6 respectively. On the 2nd “spin” I found that 3 is the #1 spot and 1,5,6,4 were eliminated from positions 2,4,5,6 respectively. Now I am trying to figure out the best odds or probabilities of where each number could end up on the 3rd and final “spin.” I am not looking for the number of combinations there are, I am looking for the odds each number has of being in a certain position.